4x^2-4x+5=8x-4

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Solution for 4x^2-4x+5=8x-4 equation: 



4x^2-4x+5=8x-4

We move all terms to the left:

4x^2-4x+5-(8x-4)=0

We get rid of parentheses

4x^2-4x-8x+4+5=0

We add all the numbers together, and all the variables

4x^2-12x+9=0

a = 4; b = -12; c = +9;
Δ = b2-4ac
Δ = -122-4·4·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{8}=1+1/2$

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